{#{QQABbQSQggCoAAJAARgCAQnICkEQkBCCAAoGQEAMMAAAgANABAA=}#}{#{QQABbQSQggCoAAJAARgCAQnICkEQkBCCAAoGQEAMMAAAgANABAA=}#}{#{QQABbQSQggCoAAJAARgCAQnICkEQkBCCAAoGQEAMMAAAgANABAA=}#}{#{QQABbQSQggCoAAJAARgCAQnICkEQkBCCAAoGQEAMMAAAgANABAA=}#}{#{QQABbQSQggCoAAJAARgCAQnICkEQkBCCAAoGQEAMMAAAgANABAA=}#}{#{QQABbQSQggCoAAJAARgCAQnICkEQkBCCAAoGQEAMMAAAgANABAA=}#}{#{QQABbQSQggCoAAJAARgCAQnICkEQkBCCAAoGQEAMMAAAgANABAA=}#}{#{QQABbQSQggCoAAJAARgCAQnICkEQkBCCAAoGQEAMMAAAgANABAA=}#}{#{QQABbQSQggCoAAJAARgCAQnICkEQkBCCAAoGQEAMMAAAgANABAA=}#}{#{QQABbQSQggCoAAJAARgCAQnICkEQkBCCAAoGQEAMMAAAgANABAA=}#}{#{QQABbQSQggCoAAJAARgCAQnICkEQkBCCAAoGQEAMMAAAgANABAA=}#}{#{QQABbQSQggCoAAJAARgCAQnICkEQkBCCAAoGQEAMMAAAgANABAA=}#}{#{QQABbQSQggCoAAJAARgCAQnICkEQkBCCAAoGQEAMMAAAgANABAA=}#}物理·评分细则说明：1.（3）的第二空，其等价形式亦对，如用2t1代替t2；2.（3）的第二空，如果没有减去半径长度，得1分。{#{QQABbQSQggCoAAJAARgCAQnICkEQkBCCAAoGQEAMMAAAgANABAA=}#}说明：1.要有必要的文字说明；2.公式书写规范；3.符号不能混乱；4.作图准确。另解：（2）碰前瞬间物块甲的动能=⑥由能量守恒可知，碰撞过程中机械能的损失量－－⑦k联立①⑦得⑧结果。~t说明：或利用动量守恒、能量守恒m=m+m1分分m+m=m+m1{#{QQABbQSQggCoAAJAARgCAQnICkEQkBCCAAoGQEAMMAAAgANABAA=}#}解得=，=，故交换速度。说明1.要有必要的文字说明；2.公式书写规范；3.符号不能混乱；4.其它合理解法也给分。{#{QQABbQSQggCoAAJAARgCAQnICkEQkBCCAAoGQEAMMAAAgANABAA=}#}说明1.要有必要的文字说明；2.公式书写规范；3.符号不能混乱；4.其他合理解法也给分。{#{QQABbQSQggCoAAJAARgCAQnICkEQkBCCAAoGQEAMMAAAgANABAA=}#}